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2024 National One Eighth physics Topic 28 Free

Black-body radiation, stefan-boltzmann and wien's laws

Riddle: stefan's law · Sub-topic 1

ONE-EIGHTH STAGE 2024

ONE-EIGHTH STAGE, ROUND 5 RIDDLES

Ampraeso SHS: 35 points (winner, qualified to the quarterfinal stage)

Anlo SHS: 31 points

Mfantsiman Girls SHS: 27 points


ROUND 5 - RIDDLE

RIDDLE

I am a named law in physics.

I am a thermophysical law.

I contain a physical constant whose value depends on the reciprocal of the speed of light squared.

I am a power-versus-temperature law.

I am the law that expresses the relationship between radiated power and the fourth power of absolute temperature.

Who am I?

ANSWER: Stefan's law (Stefan-Boltzmann law)

EXPLANATION:

The Stefan-Boltzmann law, $P=\sigma AT^4$, relates radiated power to the fourth power of absolute temperature, where $\sigma$ is the Stefan-Boltzmann constant, whose defining expression contains $\dfrac{1}{c^2}$.


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PRACTICE QUESTIONS

1. RIDDLE:

I am a law of thermal radiation.

I tell you where a hot body's spectrum peaks.

The peak wavelength and the absolute temperature have a constant product.

My constant is about $2.9\times10^{-3}$ m K.

Hotter bodies glow bluer because of me.

I am named after a German physicist who won the 1911 Nobel Prize.

Who am I?

ANSWER: WIEN'S LAW

EXPLANATION:

$\lambda_{max}T = b$, with $b \approx 2.9\times10^{-3}$ m K.


2. RIDDLE:

I am a law of thermal radiation.

I give the whole spectrum of a black body.

I assume energy comes in quanta $hf$.

I removed the ultraviolet catastrophe.

I was proposed in 1900.

Quantum theory began with me.

Who am I?

ANSWER: PLANCK'S LAW

EXPLANATION:

Planck's radiation law fits the black-body spectrum at all wavelengths by quantising energy.


3. RIDDLE:

I am a law about heat loss.

I say a body loses heat at a rate proportional to how much hotter it is than its surroundings.

I work well when that difference is small.

My temperature-time curve is exponential.

A cup of tea obeys me.

I am named after the scientist of gravitation.

Who am I?

ANSWER: NEWTON'S LAW OF COOLING

EXPLANATION:

$\dfrac{dT}{dt} = -k(T - T_s)$ for small temperature differences.


4. RIDDLE:

I am a law about how bodies take in and give out heat.

I say good absorbers are good emitters.

At equilibrium a body's emissivity equals its absorptivity.

I explain why a black kettle cools faster.

I share my author with rules for electric circuits.

I was stated in 1859.

Who am I?

ANSWER: KIRCHHOFF'S LAW OF THERMAL RADIATION

EXPLANATION:

Emissivity equals absorptivity at each wavelength for a body in thermal equilibrium.


5. RIDDLE:

I am a classical radiation law.

I work well at long wavelengths.

I predict infinite energy at short wavelengths.

I treat energy as continuous.

I am named after two British physicists.

Planck's law replaced me.

Who am I?

ANSWER: RAYLEIGH-JEANS LAW

EXPLANATION:

Classical physics gives $I \propto \dfrac{T}{\lambda^4}$, which fails at short wavelengths.


6. RIDDLE:

I am a failure of classical physics.

I was predicted for short wavelengths.

I would make a black body radiate infinite energy.

Quantisation of energy removed me.

My name points to the violet end and beyond.

My name also suggests a disaster.

Who am I?

ANSWER: ULTRAVIOLET CATASTROPHE

EXPLANATION:

The Rayleigh-Jeans law predicts unlimited emission at short wavelengths; Planck's quanta solve it.


7. RIDDLE:

I am a number between 0 and 1.

I compare a surface's radiation with that of a black body.

A perfect black body has 1 for me.

Polished silver has a very small value of me.

I appear in $P = e\sigma AT^4$.

Good absorbers have a large value of me.

Who am I?

ANSWER: EMISSIVITY

EXPLANATION:

Emissivity is the ratio of a surface's radiated power to that of a black body at the same temperature.


8. RIDDLE:

I am an instrument.

I measure very high temperatures.

I do not touch the hot object.

I compare the colour or brightness of its glow.

Furnaces and molten metals are measured with me.

My name comes from the Greek for fire.

Who am I?

ANSWER: PYROMETER

EXPLANATION:

An optical pyrometer finds temperature from the radiation a hot body emits.


9. RIDDLE:

I am an early idea about heat exchange.

I say every body radiates, whatever its temperature.

A body at the same temperature as its surroundings gives and takes equally.

I explain why a body in equilibrium stays at constant temperature.

I was proposed in 1791.

I am named after a Swiss physicist.

Who am I?

ANSWER: PREVOST'S THEORY OF EXCHANGES

EXPLANATION:

Bodies continually emit and absorb radiation; equilibrium means equal rates.