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2026 National Semi Final chemistry Topic 15 Free

Chemical kinetics

Rate constant with units from a rate law r = k[a]^2[b]^3 · Sub-topic 1

SEMI FINAL STAGE 2026

Mfantsipim School: 56 points

Presbyterian Boys' Sec. Sch: 53 points

Osei Tutu SHS: 27 points


QUESTION

The rate law for a reaction between reactants A and B is given by $R=k[\text{A}]^2[\text{B}]^3$.

What is the rate constant and its units for a reaction in which

$[\text{A}] = [\text{B}]$

$[\text{A}] = 0.200$

mol/dm³, and the rate is $2.00\times10^{-4}$ mol/dm³/s?

NOTE: In a rate law, $k$ is the rate constant, a kinetics quantity, not an equilibrium constant.

The number/units below answer what was actually asked.

ANSWER: $k=6.25\times10^{-1}$ mol$^{-4}$dm$^{12}$s$^{-1}$

SOLUTION:

$k = \dfrac{R}{[\text{A}]^2[\text{B}]^3}$

$k = \dfrac{2.00\times10^{-4}}{(0.200)^2(0.200)^3}$

$k = \dfrac{2.00\times10^{-4}}{(0.200)^5}$

$(0.200)^5=3.2\times10^{-4}$, so

$k = \dfrac{2.00\times10^{-4}}{3.2\times10^{-4}}$

$k = \dfrac{2\times10^{-4}}{32\times10^{-5}}$

$k = \dfrac{1}{16} \times10^{1}$

$k = 0.625$

$k = 6.25\times10^{-1}$

Units shortcut: for overall order $n$ (here

$n = 2+3$

$n = 5$

), $k$'s units are always mol$^{1-n}$dm$^{3(n-1)}$s$^{-1}$.

With $n=5$: mol$^{-4}$dm$^{12}$s$^{-1}$.


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PRACTICE QUESTIONS

1. QUESTION: The rate law for a reaction is $R=k[\text{A}][\text{B}]^2$. What is the rate constant and its units when [A] = [B] = 0.100 mol/dm³ and the rate is $2.00\times10^{-5}$ mol/dm³/s?

ANSWER: $k = 2.00\times10^{-2}$ mol⁻² dm⁶ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}][\text{B}]^2}$

$k = \dfrac{2.00\times10^{-5}}{1.00\times10^{-3}}$

$k = \dfrac{2\times10^{-5}}{10^{-3}}$

$k = 2.00\times10^{-2}$

Units: mol⁻² dm⁶ s⁻¹


2. QUESTION: The rate law for a reaction is $R=k[\text{A}]^2$. What is the rate constant and its units when [A] = 0.300 mol/dm³ and the rate is $4.50\times10^{-3}$ mol/dm³/s?

ANSWER: $k = 5.00\times10^{-2}$ dm³ mol⁻¹ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}]^2}$

$k = \dfrac{4.50\times10^{-3}}{9.00\times10^{-2}}$

$k = \dfrac{45\times10^{-4}}{9\times10^{-2}}$

$k = 5.00\times10^{-2}$

Units: dm³ mol⁻¹ s⁻¹


3. QUESTION: The rate law for a reaction is $R=k[\text{A}]^2[\text{B}]$. What is the rate constant and its units when [A] = [B] = 0.200 mol/dm³ and the rate is $1.20\times10^{-3}$ mol/dm³/s?

ANSWER: $k = 0.150$ mol⁻² dm⁶ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}]^2[\text{B}]}$

$k = \dfrac{1.20\times10^{-3}}{8.00\times10^{-3}}$

$k = \dfrac{12\times10^{-4}}{8\times10^{-3}}$

$k = \dfrac{3}{2} \times10^{-1}$

$k = 0.150$

Units: mol⁻² dm⁶ s⁻¹


4. QUESTION: The rate law for a reaction is $R=k[\text{A}][\text{B}]$. What is the rate constant and its units when [A] = [B] = 0.200 mol/dm³ and the rate is $8.00\times10^{-4}$ mol/dm³/s?

ANSWER: $k = 2.00\times10^{-2}$ dm³ mol⁻¹ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}][\text{B}]}$

$k = \dfrac{8.00\times10^{-4}}{4.00\times10^{-2}}$

$k = \dfrac{8\times10^{-4}}{4\times10^{-2}}$

$k = 2.00\times10^{-2}$

Units: dm³ mol⁻¹ s⁻¹


5. QUESTION: The rate law for a reaction is $R=k[\text{A}]$. What is the rate constant and its units when [A] = 0.250 mol/dm³ and the rate is $7.50\times10^{-3}$ mol/dm³/s?

ANSWER: $k = 3.00\times10^{-2}$ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}]}$

$k = \dfrac{7.50\times10^{-3}}{0.250}$

$k = \dfrac{75\times10^{-4}}{25\times10^{-2}}$

$k = 3.00\times10^{-2}$

Units: s⁻¹


6. QUESTION: The rate law for a reaction is $R=k[\text{A}]^2[\text{B}]$. What is the rate constant and its units when [A] = [B] = 0.100 mol/dm³ and the rate is $3.00\times10^{-4}$ mol/dm³/s?

ANSWER: $k = 0.300$ mol⁻² dm⁶ s⁻¹

SOLUTION:

$k = \dfrac{R}{[\text{A}]^2[\text{B}]}$

$k = \dfrac{3.00\times10^{-4}}{1.00\times10^{-3}}$

$k = \dfrac{3\times10^{-4}}{10^{-3}}$

$k = 0.300$

Units: mol⁻² dm⁶ s⁻¹