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2024 National Preliminary mathematics Topic 25 Free

Linear equations, inequalities and word problems

Solving $2x-5\lt3x+8\lt2x+5$, a compound linear inequality · Sub-topic 1

PRELIMINARY CONTEST 2024

Contest 28

St. John’s Grammar School – 38 pts (Winner)

Accra High School – 32 pts

St. Francis Girls’ SHS – 13 pts

Contest 29

Kumasi Academy – 56 pts (Winner)

Saviour SHS – 16 pts

Battor SHS – 14 pts

Contest 30

Ghana SHS, Koforidua – 49 pts (Winner)

Sefwi Wiawso SHS – 15 pts

Northern School of Business – 09 pts


ROUND 1

QUESTION 1

Solve the compound linear inequality $2x-5<3x+8<2x+5$.

ANSWER: $-13 < x < -3$


SOLUTION

Break into two inequalities:

Inequality 1:

$2x-5<3x+8$

$2x-3x<8+5$

$-x<13$

$x>-13$

Inequality 2:

$3x+8<2x+5$

$3x-2x<5-8$

$x<-3$

Combine the results:

$x>-13\text{ and }x<-3$

$-13<x<-3$


QUESTION 2

Solve the compound linear inequality $8-x<2x+2<11-x$.

ANSWER: $2 < x < 3$


SOLUTION

Break into two inequalities:

Inequality 1:

$8-x<2x+2$

$-x-2x<2-8$

$-3x<-6$

$\dfrac{-3x}{-3}>\dfrac{-6}{-3}$

$x>2$

Inequality 2:

$2x+2<11-x$

$2x+x<11-2$

$3x<9$

$\dfrac{3x}{3}<\dfrac{9}{3}$

$x<3$

Combine the results:

$x>2\text{ and }x<3$

$2<x<3$


QUESTION 3

Solve the compound linear inequality $x-12<3x-4<x+12$.

ANSWER: $-4 < x < 8$


SOLUTION

Break into two inequalities:

Inequality 1:

$x-12<3x-4$

$x-3x<-4+12$

$-2x<8$

$\dfrac{-2x}{-2}>\dfrac{8}{-2}$

$x>-4$

Inequality 2:

$3x-4<x+12$

$3x-x<12+4$

$2x<16$

$\dfrac{2x}{2}<\dfrac{16}{2}$

$x<8$

Combine the results:

$x>-4\text{ and }x<8$

$-4<x<8$


PRACTICE QUESTIONS


1. Solve the compound linear inequality $-2x+1\lt-3x+8\lt-2x+14$.

ANSWER: $-6\lt x\lt 7$


SOLUTION

Break into two inequalities.

Inequality 1:

$-2x+1\lt-3x+8$

$-2x+3x\lt8-1$

$x\lt 7$

Inequality 2:

$-3x+8\lt-2x+14$

$-3x+2x\lt14-8$

$-x\lt6$

Multiply by $-1$ and reverse the inequality sign:

$x\gt -6$

Combine the results:

$-6\lt x\lt 7$


2. Solve the compound linear inequality $-3x-11\lt-4x+3\lt-2x+8$.

ANSWER: $-\dfrac{5}{2}\lt x\lt 14$


SOLUTION

Break into two inequalities.

Inequality 1:

$-3x-11\lt-4x+3$

$-3x+4x\lt3+11$

$x\lt 14$

Inequality 2:

$-4x+3\lt-2x+8$

$-4x+2x\lt8-3$

$-2x\lt5$

Divide by $-2$ and reverse the inequality sign:

$x\gt -\dfrac{5}{2}$

Combine the results:

$-\dfrac{5}{2}\lt x\lt 14$


3. Solve the compound linear inequality $3x+3\ltx-2\lt2x+10$.

ANSWER: $-12\lt x\lt -\dfrac{5}{2}$


SOLUTION

Break into two inequalities.

Inequality 1:

$3x+3\ltx-2$

$3x-x\lt-2-3$

$2x\lt-5$

Divide by $2$:

$x\lt -\dfrac{5}{2}$

Inequality 2:

$x-2\lt2x+10$

$x-2x\lt10+2$

$-x\lt12$

Multiply by $-1$ and reverse the inequality sign:

$x\gt -12$

Combine the results:

$-12\lt x\lt -\dfrac{5}{2}$


4. Solve the compound linear inequality $-2x-10\ltx-1\lt-x-5$.

ANSWER: $-3\lt x\lt -2$


SOLUTION

Break into two inequalities.

Inequality 1:

$-2x-10\ltx-1$

$-2x-x\lt-1+10$

$-3x\lt9$

Divide by $-3$ and reverse the inequality sign:

$x\gt -3$

Inequality 2:

$x-1\lt-x-5$

$x+x\lt-5+1$

$2x\lt-4$

Divide by $2$:

$x\lt -2$

Combine the results:

$-3\lt x\lt -2$


5. Solve the compound linear inequality $3x-6\lt2x+12\lt3x-2$.

ANSWER: $14\lt x\lt 18$


SOLUTION

Break into two inequalities.

Inequality 1:

$3x-6\lt2x+12$

$3x-2x\lt12+6$

$x\lt 18$

Inequality 2:

$2x+12\lt3x-2$

$2x-3x\lt-2-12$

$-x\lt-14$

Multiply by $-1$ and reverse the inequality sign:

$x\gt 14$

Combine the results:

$14\lt x\lt 18$


6. Solve the compound linear inequality $-x+1\lt3x+1\lt2x+12$.

ANSWER: $0\lt x\lt 11$


SOLUTION

Break into two inequalities.

Inequality 1:

$-x+1\lt3x+1$

$-x-3x\lt1-1$

$-4x\lt0$

Divide by $-4$ and reverse the inequality sign:

$x\gt 0$

Inequality 2:

$3x+1\lt2x+12$

$3x-2x\lt12-1$

$x\lt 11$

Combine the results:

$0\lt x\lt 11$